36x^2-108x+81=

Solution for 36x^2-108x+81= equation:

36x^2-108x+81=

We move all terms to the left:

36x^2-108x+81-()=0

We add all the numbers together, and all the variables

36x^2-108x=0

a = 36; b = -108; c = 0;
Δ = b2-4ac
Δ = -1082-4·36·0
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-108}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+108}{2*36}=\frac{216}{72}
=3
$